Write a function that takes an unsigned integer and returns the number of ’1′ bits it has (also known as the Hamming weight).
For example, the 32-bit integer ’11′ has binary representation 00000000000000000000000000001011, so the function should return 3.
//数出十进制转换成二进制后的数有多少个1,亦或本身减一然后计数
public class Solution { // you need to treat n as an unsigned value public int hammingWeight(int n) { int count = 0; while(n!=0){ count++; n = n & (n-1); } return count; } }