Given two binary strings, return their sum (also a binary string).
For example,
a = "11"
b = "1"
Return "100"
.
// String.valueOf(1) 可以转换int 1为String类型的”1″
// 将较长的数字放到前面,可以简化代码
// 强制转换成了int也简化了4种if的情况
public class Solution { public String addBinary(String a, String b) { if(a.length() < b.length()){ String tmp = a; a = b; b = tmp; } int pa = a.length()-1; int pb = b.length()-1; int carries = 0; String rst = ""; while(pb >= 0){ int sum = (int)(a.charAt(pa) - '0') + (int)(b.charAt(pb) - '0') + carries; rst = String.valueOf(sum % 2) + rst; carries = sum / 2; pa --; pb --; } while(pa >= 0){ int sum = (int)(a.charAt(pa) - '0') + carries; rst = String.valueOf(sum % 2) + rst; carries = sum / 2; pa --; } if (carries == 1) rst = "1" + rst; return rst; } }